将充满逗号分隔值的varchar传递给SQL Server IN函数

重复的
动态SQL逗号分隔值查询
具有Like和In的参数化查询

我有一个SQL Server存储过程,我想将一个充满逗号分隔值的varchar传递给IN函数。 例如:

DECLARE @Ids varchar(50);
SET @Ids = '1,2,3,5,4,6,7,98,234';

SELECT * 
FROM sometable 
WHERE tableid IN (@Ids);

当然这是行不通的。 我收到错误:

将varchar值'1,2,3,5,4,6,7,98,234'转换为数据类型int时转换失败。

如何在不借助动态SQL的情况下完成此操作(或相对类似的操作)?

Vance Smith asked 2020-01-13T12:42:12Z
22个解决方案
56 votes

当然,如果您像我一样懒惰,可以这样做:

Declare @Ids varchar(50) Set @Ids = ',1,2,3,5,4,6,7,98,234,'

Select * from sometable
 where Charindex(','+cast(tableid as varchar(8000))+',', @Ids) > 0
RBarryYoung answered 2020-01-13T12:43:16Z
43 votes

不要使用循环拆分字符串的函数!我下面的函数将非常快速地拆分字符串,而不会循环!

在使用我的函数之前,您需要设置一个“帮助器”表,每个数据库只需要执行一次此操作:

CREATE TABLE Numbers
(Number int  NOT NULL,
    CONSTRAINT PK_Numbers PRIMARY KEY CLUSTERED (Number ASC)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]
DECLARE @x int
SET @x=0
WHILE @x<8000
BEGIN
    SET @x=@x+1
    INSERT INTO Numbers VALUES (@x)
END

使用此函数拆分您的字符串,该字符串不会循环并且非常快:

CREATE FUNCTION [dbo].[FN_ListToTable]
(
     @SplitOn              char(1)              --REQUIRED, the character to split the @List string on
    ,@List                 varchar(8000)        --REQUIRED, the list to split apart
)
RETURNS
@ParsedList table
(
    ListValue varchar(500)
)
AS
BEGIN

/**
Takes the given @List string and splits it apart based on the given @SplitOn character.
A table is returned, one row per split item, with a column name "ListValue".
This function workes for fixed or variable lenght items.
Empty and null items will not be included in the results set.


Returns a table, one row per item in the list, with a column name "ListValue"

EXAMPLE:
----------
SELECT * FROM dbo.FN_ListToTable(',','1,12,123,1234,54321,6,A,*,|||,,,,B')

    returns:
        ListValue  
        -----------
        1
        12
        123
        1234
        54321
        6
        A
        *
        |||
        B

        (10 row(s) affected)

**/



----------------
--SINGLE QUERY-- --this will not return empty rows
----------------
INSERT INTO @ParsedList
        (ListValue)
    SELECT
        ListValue
        FROM (SELECT
                  LTRIM(RTRIM(SUBSTRING(List2, number+1, CHARINDEX(@SplitOn, List2, number+1)-number - 1))) AS ListValue
                  FROM (
                           SELECT @SplitOn + @List + @SplitOn AS List2
                       ) AS dt
                      INNER JOIN Numbers n ON n.Number < LEN(dt.List2)
                  WHERE SUBSTRING(List2, number, 1) = @SplitOn
             ) dt2
        WHERE ListValue IS NOT NULL AND ListValue!=''



RETURN

END --Function FN_ListToTable

您可以将此函数用作联接中的表:

SELECT
    Col1, COl2, Col3...
    FROM  YourTable
        INNER JOIN FN_ListToTable(',',@YourString) s ON  YourTable.ID = s.ListValue

这是您的示例:

Select * from sometable where tableid in(SELECT ListValue FROM dbo.FN_ListToTable(',',@Ids) s)
KM. answered 2020-01-13T12:42:56Z
18 votes

没有表没有功能没有循环

基于将您的列表解析为表格的想法,我们的DBA建议使用XML。

Declare @Ids varchar(50)
Set @Ids = ‘1,2,3,5,4,6,7,98,234’

DECLARE @XML XML
SET @XML = CAST('<i>' + REPLACE(@Ids, ',', '</i><i>') + '</i>' AS XML)

SELECT * 
FROM
    SomeTable 
    INNER JOIN @XML.nodes('i') x(i) 
        ON  SomeTable .Id = x.i.value('.', 'VARCHAR(MAX)')

这些似乎与@KM的答案具有相同的性能,但我认为它要简单得多。

CeejeeB answered 2020-01-13T12:43:44Z
11 votes

您可以创建一个返回表的函数。

所以你的陈述就像

select * from someable 
 join Splitfunction(@ids) as splits on sometable.id = splits.id

这是一个类似的功能。

CREATE FUNCTION [dbo].[FUNC_SplitOrderIDs]
(
    @OrderList varchar(500)
)
RETURNS 
@ParsedList table
(
    OrderID int
)
AS
BEGIN
    DECLARE @OrderID varchar(10), @Pos int

    SET @OrderList = LTRIM(RTRIM(@OrderList))+ ','
    SET @Pos = CHARINDEX(',', @OrderList, 1)

    IF REPLACE(@OrderList, ',', '') <> ''
    BEGIN
        WHILE @Pos > 0
        BEGIN
            SET @OrderID = LTRIM(RTRIM(LEFT(@OrderList, @Pos - 1)))
            IF @OrderID <> ''
            BEGIN
                INSERT INTO @ParsedList (OrderID) 
                VALUES (CAST(@OrderID AS int)) --Use Appropriate conversion
            END
            SET @OrderList = RIGHT(@OrderList, LEN(@OrderList) - @Pos)
            SET @Pos = CHARINDEX(',', @OrderList, 1)

        END
    END 
    RETURN
END
Richard L answered 2020-01-13T12:44:13Z
10 votes

这是一个非常普遍的问题。 罐头答案,几种不错的技巧:

[http://www.sommarskog.se/arrays-in-sql-2005.html]

A-K answered 2020-01-13T12:44:39Z
8 votes

这样完美! 以下答案过于复杂。 不要认为这是动态的。 设置存储过程,如下所示:

(@id as varchar(50))
as

Declare @query as nvarchar(max)
set @query ='
select * from table
where id in('+@id+')'
EXECUTE sp_executesql @query
Eric answered 2020-01-13T12:44:59Z
6 votes

在不使用动态SQL的情况下,您必须采用输入变量并使用split函数将数据放入临时表中,然后将其联接。

HLGEM answered 2020-01-13T12:45:21Z
5 votes

我可以建议像这样使用WITH

DECLARE @Delim char(1) = ',';
SET @Ids = @Ids + @Delim;

WITH CTE(i, ls, id) AS (
    SELECT 1, CHARINDEX(@Delim, @Ids, 1), SUBSTRING(@Ids, 1, CHARINDEX(@Delim, @Ids, 1) - 1)
    UNION ALL
    SELECT i + 1, CHARINDEX(@Delim, @Ids, ls + 1), SUBSTRING(@Ids, ls + 1, CHARINDEX(@Delim, @Ids, ls + 1) - CHARINDEX(@Delim, @Ids, ls) - 1)
    FROM CTE
    WHERE  CHARINDEX(@Delim, @Ids, ls + 1) > 1
)
SELECT t.*
FROM yourTable t
    INNER JOIN
    CTE c
    ON t.id = c.id;
shA.t answered 2020-01-13T12:45:41Z
3 votes

谢谢,您已使用我的功能.....................这是我的例子

**UPDATE [RD].[PurchaseOrderHeader]
SET     [DispatchCycleNumber] ='10'
 WHERE  OrderNumber in(select * FROM XA.fn_SplitOrderIDs(@InvoiceNumberList))**


CREATE FUNCTION [XA].[fn_SplitOrderIDs]
(
    @OrderList varchar(500)
)
RETURNS 
@ParsedList table
(
    OrderID int
)
AS
BEGIN
    DECLARE @OrderID varchar(10), @Pos int

    SET @OrderList = LTRIM(RTRIM(@OrderList))+ ','
    SET @Pos = CHARINDEX(',', @OrderList, 1)

    IF REPLACE(@OrderList, ',', '') <> ''
    BEGIN
        WHILE @Pos > 0
        BEGIN
                SET @OrderID = LTRIM(RTRIM(LEFT(@OrderList, @Pos - 1)))
                IF @OrderID <> ''
                BEGIN
                        INSERT INTO @ParsedList (OrderID) 
                        VALUES (CAST(@OrderID AS int)) --Use Appropriate conversion
                END
                SET @OrderList = RIGHT(@OrderList, LEN(@OrderList) - @Pos)
                SET @Pos = CHARINDEX(',', @OrderList, 1)

        END
    END 
    RETURN
END
nadee85 answered 2020-01-13T12:46:01Z
3 votes

如果使用SQL Server 2008或更高版本,请使用表值参数;否则,请使用表值参数。 例如:

CREATE PROCEDURE [dbo].[GetAccounts](@accountIds nvarchar)
AS
BEGIN
    SELECT * 
    FROM accountsTable 
    WHERE accountId IN (select * from @accountIds)
END

CREATE TYPE intListTableType AS TABLE (n int NOT NULL)

DECLARE @tvp intListTableType 

-- inserts each id to one row in the tvp table    
INSERT @tvp(n) VALUES (16509),(16685),(46173),(42925),(46167),(5511)

EXEC GetAccounts @tvp
BornToCode answered 2020-01-13T12:46:21Z
3 votes

创建一个像下面这样的表函数,该函数解析逗号分隔的varchar并返回一个可以与其他表进行内部联接的表。

CREATE FUNCTION [dbo].[fn_SplitList]
(
  @inString     varchar(MAX)  = '',
  @inDelimiter  char(1)       = ',' -- Keep the delimiter to 100 chars or less.  Generally a delimiter will be 1-2 chars only.
)
RETURNS @tbl_Return  table
(
  Unit  varchar(1000) COLLATE Latin1_General_BIN
)
AS
BEGIN 
    INSERT INTO @tbl_Return
    SELECT DISTINCT
      LTRIM(RTRIM(piece.value('./text()[1]', 'varchar(1000)'))) COLLATE DATABASE_DEFAULT AS Unit
    FROM
    (
      --
      --  Replace any delimiters in the string with the "X" tag.
      --
      SELECT
        CAST(('<X>' + REPLACE(s0.prsString, s0.prsSplitDelimit, '</X><X>') + '</X>') AS xml).query('.') AS units
      FROM
      (
        --
        --  Convert the string and delimiter into XML.
        --
        SELECT
          (SELECT @inString FOR XML PATH('')) AS prsString,
          (SELECT @inDelimiter FOR XML PATH('')) AS prsSplitDelimit
      ) AS s0
    ) AS s1
    CROSS APPLY units.nodes('X') x(piece)
  RETURN
END

=================================================现在,在代码中使用上面创建的表函数,函数的创建是数据库中的一项活动,可在同一服务器上的多个数据库中使用。

DECLARE @Ids varchar(50);
SET @Ids = '1,2,3,5,4,6,7,98,234';

SELECT
     *
FROM sometable AS st
INNER JOIN fn_SplitList(@ids, ',') AS sl
     ON sl.unit = st.tableid
Shakti Singh Chauhan answered 2020-01-13T12:46:47Z
3 votes

我认为可以采用以下非常简单的解决方案:

DECLARE @Ids varchar(50);
SET @Ids = '1,2,3,5,4,6,7,98,234';

SELECT * 
FROM sometable 
WHERE ','+@Ids+',' LIKE '%,'+CONVERT(VARCHAR(50),tableid)+',%';
user1400290 answered 2020-01-13T12:47:08Z
2 votes

我已经写了一个存储过程来展示如何做到这一点。您基本上必须处理字符串。我试图在这里发布代码,但是格式变得很麻烦。

IF EXISTS (SELECT * FROM dbo.sysobjects WHERE id = object_id(N'[dbo].[uspSplitTextList]') AND OBJECTPROPERTY(id, N'IsProcedure') = 1)
   DROP PROCEDURE [dbo].[uspSplitTextList]
GO

SET QUOTED_IDENTIFIER ON 
GO
SET ANSI_NULLS ON 
GO


/* ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ */
-- uspSplitTextList
--
-- Description:
--    splits a separated list of text items and returns the text items
--
-- Arguments:
--    @list_text        - list of text items
--    @Delimiter        - delimiter
--
-- Notes:
-- 02/22/2006 - WSR : use DATALENGTH instead of LEN throughout because LEN doesn't count trailing blanks
--
-- History:
-- 02/22/2006 - WSR : revised algorithm to account for items crossing 8000 character boundary
-- 09/18/2006 - WSR : added to this project
--
CREATE PROCEDURE uspSplitTextList
   @list_text           text,
   @Delimiter           varchar(3)
AS

SET NOCOUNT ON

DECLARE @InputLen       integer         -- input text length
DECLARE @TextPos        integer         -- current position within input text
DECLARE @Chunk          varchar(8000)   -- chunk within input text
DECLARE @ChunkPos       integer         -- current position within chunk
DECLARE @DelimPos       integer         -- position of delimiter
DECLARE @ChunkLen       integer         -- chunk length
DECLARE @DelimLen       integer         -- delimiter length
DECLARE @ItemBegPos     integer         -- item starting position in text
DECLARE @ItemOrder      integer         -- item order in list
DECLARE @DelimChar      varchar(1)      -- first character of delimiter (simple delimiter)

-- create table to hold list items
-- actually their positions because we may want to scrub this list eliminating bad entries before substring is applied
CREATE TABLE #list_items ( item_order integer, item_begpos integer, item_endpos integer )

-- process list
IF @list_text IS NOT NULL
   BEGIN

   -- initialize
   SET @InputLen = DATALENGTH(@list_text)
   SET @TextPos = 1
   SET @DelimChar = SUBSTRING(@Delimiter, 1, 1)
   SET @DelimLen = DATALENGTH(@Delimiter)
   SET @ItemBegPos = 1
   SET @ItemOrder = 1
   SET @ChunkLen = 1

   -- cycle through input processing chunks
   WHILE @TextPos <= @InputLen AND @ChunkLen <> 0
      BEGIN

      -- get current chunk
      SET @Chunk = SUBSTRING(@list_text, @TextPos, 8000)

      -- setup initial variable values
      SET @ChunkPos = 1
      SET @ChunkLen = DATALENGTH(@Chunk)
      SET @DelimPos = CHARINDEX(@DelimChar, @Chunk, @ChunkPos)

      -- loop over the chunk, until the last delimiter
      WHILE @ChunkPos <= @ChunkLen AND @DelimPos <> 0
         BEGIN

         -- see if this is a full delimiter
         IF SUBSTRING(@list_text, (@TextPos + @DelimPos - 1), @DelimLen) = @Delimiter
            BEGIN

            -- insert position
            INSERT INTO #list_items (item_order, item_begpos, item_endpos)
            VALUES (@ItemOrder, @ItemBegPos, (@TextPos + @DelimPos - 1) - 1)

            -- adjust positions
            SET @ItemOrder = @ItemOrder + 1
            SET @ItemBegPos = (@TextPos + @DelimPos - 1) + @DelimLen
            SET @ChunkPos = @DelimPos + @DelimLen

            END
         ELSE
            BEGIN

            -- adjust positions
            SET @ChunkPos = @DelimPos + 1

            END

         -- find next delimiter      
         SET @DelimPos = CHARINDEX(@DelimChar, @Chunk, @ChunkPos)

         END

      -- adjust positions
      SET @TextPos = @TextPos + @ChunkLen

      END

   -- handle last item
   IF @ItemBegPos <= @InputLen
      BEGIN

      -- insert position
      INSERT INTO #list_items (item_order, item_begpos, item_endpos)
      VALUES (@ItemOrder, @ItemBegPos, @InputLen)

      END

   -- delete the bad items
   DELETE FROM #list_items
   WHERE item_endpos < item_begpos

   -- return list items
   SELECT SUBSTRING(@list_text, item_begpos, (item_endpos - item_begpos + 1)) AS item_text, item_order, item_begpos, item_endpos
   FROM #list_items
   ORDER BY item_order

   END

DROP TABLE #list_items

RETURN

/* ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ */

GO
SET QUOTED_IDENTIFIER OFF 
GO
SET ANSI_NULLS ON 
GO
Will Rickards answered 2020-01-13T12:47:29Z
2 votes

已经有一段时间了,但是我过去使用XML作为过渡来做到这一点。

我对此一无所获,但恐怕我再也不知道我从哪里得到这个主意了:

-- declare the variables needed
DECLARE @xml as xml,@str as varchar(100),@delimiter as varchar(10)

-- The string you want to split
SET @str='A,B,C,D,E,Bert,Ernie,1,2,3,4,5'

-- What you want to split on. Can be a single character or a string
SET @delimiter =','

-- Convert it to an XML document
SET @xml = cast(('<X>'+replace(@str,@delimiter ,'</X><X>')+'</X>') as xml)

-- Select back from the XML
SELECT N.value('.', 'varchar(10)') as value FROM @xml.nodes('X') as T(N)
Morvael answered 2020-01-13T12:47:54Z
2 votes

我对KM用户有相同的想法。 但不需要额外的表号。 仅此功能而已。

CREATE FUNCTION [dbo].[FN_ListToTable]
(
    @SplitOn              char(1)              --REQUIRED, the character to split the @List string on
   ,@List                 varchar(8000)        --REQUIRED, the list to split apart
)
RETURNS
@ParsedList table
(
    ListValue varchar(500)
)
AS
BEGIN
    DECLARE @number int = 0
    DECLARE @childString varchar(502) = ''
    DECLARE @lengthChildString int = 0
    DECLARE @processString varchar(502) = @SplitOn + @List + @SplitOn

    WHILE @number < LEN(@processString)
    BEGIN
        SET @number = @number + 1
        SET @lengthChildString = CHARINDEX(@SplitOn, @processString, @number + 1) - @number - 1
        IF @lengthChildString > 0
        BEGIN
            SET @childString = LTRIM(RTRIM(SUBSTRING(@processString, @number + 1, @lengthChildString)))

            IF @childString IS NOT NULL AND @childString != ''
            BEGIN
                INSERT INTO @ParsedList(ListValue) VALUES (@childString)
                SET @number = @number + @lengthChildString - 1
            END
        END
    END

RETURN

END

这是测试:

SELECT ListValue FROM dbo.FN_ListToTable('/','a/////bb/c')

结果:

   ListValue
______________________
   a
   bb
   c
Thế Anh Nguyễn answered 2020-01-13T12:48:23Z
2 votes

尝试这个:

SELECT ProductId, Name, Tags  
FROM Product  
WHERE '1,2,3,' LIKE '%' + CAST(ProductId AS VARCHAR(20)) + ',%'; 

如在此链接的最后一个示例中所述

eric_awa answered 2020-01-13T12:48:47Z
1 votes
-- select * from dbo.Split_ID('77,106')  

    ALTER FUNCTION dbo.Split_ID(@String varchar(8000))     
    returns @temptable TABLE (ID varchar(8000))     
    as     
    begin     
        declare @idx int     
        declare @slice varchar(8000)     
        declare @Delimiter char(1)
         set @Delimiter =','

        select @idx = 1     
            if len(@String)<1 or @String is null  return     

        while @idx!= 0     
        begin     
            set @idx = charindex(@Delimiter,@String)     
            if @idx!=0     
                set @slice = left(@String,@idx - 1)     
            else     
                set @slice = @String     

            if(len(@slice)>0)
                insert into @temptable(ID) values(@slice)     

            set @String = right(@String,len(@String) - @idx)     
            if len(@String) = 0 break     
        end 
    return     
    end
BJ Patel answered 2020-01-13T12:49:02Z
1 votes

您可以这样做:

create or replace 
PROCEDURE UDP_SETBOOKMARK 
(
  P_USERID IN VARCHAR2  
, P_BOOKMARK IN VARCHAR2  
) AS 
BEGIN

UPDATE T_ER_Bewertung
SET LESEZEICHEN = P_BOOKMARK
WHERE STAMM_ID in( select regexp_substr(P_USERID,'[^,]+', 1, level) from dual
                   connect by regexp_substr(P_USERID, '[^,]+', 1, level) is not null )
and ER_ID = (select max(ER_ID) from T_ER_Bewertung_Kopie);

commit;

END UDP_SETBOOKMARK;

然后尝试

Begin
UDP_SETBOOKMARK ('1,2,3,4,5', 'Test');
End;

您也可以在其他情况下将此IN-Clause与regexp_substr一起使用,只需尝试一下即可。

Salfii answered 2020-01-13T12:49:31Z
1 votes
Error 493: The column 'i' that was returned from the nodes() method cannot be 
   used directly. It can only be used with one of the four XML data type 
   methods, exist(), nodes(), query(), and value(), or in IS NULL and IS NOT 
   NULL checks.

通过使用以下代码段,在SQL Server 2014中修复了上述错误

Declare @Ids varchar(50)
Set @Ids = '1,2,3,5,4,6,7,98,234'

DECLARE @XML XML
SET @XML = CAST('<i>' + REPLACE(@Ids, ',', '</i><i>') + '</i>' AS XML)

SELECT SomeTable.* 
FROM
    SomeTable 
    cross apply @XML.nodes('i') x(i) 
        where SomeTable .Id = x.i.value('.', 'VARCHAR(MAX)')
Amaldev answered 2020-01-13T12:49:51Z
0 votes

最佳而简单的方法。

DECLARE @AccumulateKeywordCopy NVARCHAR(2000),@IDDupCopy NVARCHAR(50);
SET @AccumulateKeywordCopy ='';
SET @IDDupCopy ='';
SET @IDDup = (SELECT CONVERT(VARCHAR(MAX), <columnName>) FROM <tableName> WHERE <clause>)

SET @AccumulateKeywordCopy = ','+@AccumulateKeyword+',';
SET @IDDupCopy = ','+@IDDup +',';
SET @IDDupCheck = CHARINDEX(@IDDupCopy,@AccumulateKeywordCopy)
Vishu answered 2020-01-13T12:50:13Z
0 votes
CREATE TABLE t 
  ( 
     id   INT, 
     col1 VARCHAR(50) 
  ) 

INSERT INTO t 
VALUES     (1, 
            'param1') 

INSERT INTO t 
VALUES     (2, 
            'param2') 

INSERT INTO t 
VALUES     (3, 
            'param3') 

INSERT INTO t 
VALUES     (4, 
            'param4') 

INSERT INTO t 
VALUES     (5, 
            'param5') 

DECLARE @params VARCHAR(100) 

SET @params = ',param1,param2,param3,' 

SELECT * 
FROM   t 
WHERE  Charindex(',' + Cast(col1 AS VARCHAR(8000)) + ',', @params) > 0 

工作小提琴在这里找到

Kapila Perera answered 2020-01-13T12:50:33Z
0 votes

我发现的最简单方法是使用FIND_IN_SET

FIND_IN_SET(column_name, values)

values=(1,2,3)

SELECT name WHERE FIND_IN_SET(id, values)
Ashmita Jain answered 2020-01-13T12:50:53Z
translate from https://stackoverflow.com:/questions/878833/passing-a-varchar-full-of-comma-delimited-values-to-a-sql-server-in-function